# What is the equation of a circle?

## What is the equation of a circle?

The standard equation of a circle is given by: (x-h) 2 + (y-k) 2 = r 2. Where (h,k) is the coordinates of center of the circle and r is the radius. Before deriving the equation of a circle, let us focus on what is a circle? A circle is a set of all points which are equally spaced from a fixed point in a plane.

**What is the molecular process of anammox reaction?**

Molecular Process of the Anammox Reaction. These catabolic reactions occur within the anammoxosome, a specialized pseudo-organelle within the bacterium, and create a proton gradient across the anammoxosome membrane [12]. The first step involves the reduction of nitrite to nitric oxide by nitrate reductase (NirS).

### What is the standard form of the circle equation?

Standard form of circle equation is (x – a) 2 + (y – b) 2 = r 2 Substituting the values of centre and radius, (x – 2) 2 + (y – 3) 2 = 1 2 x 2 – 4x + 4 + y 2 – 6y + 9 = 1

**How do you find the circle of a point?**

So the circle is all the points (x,y) that are “r” away from the center (a,b). Now lets work out where the points are (using a right-angled triangle and Pythagoras): It is the same idea as before, but we need to subtract a and b: (x−a) 2 + (y−b) 2 = r 2.

## How to find lattice points of a given equation?

Recommended: Please solve it on “ PRACTICE ” first, before moving on to the solution. To find lattice points, we basically need to find values of (x, y) which satisfy the equation x 2 + y 2 = r 2 . For any value of (x, y) that satisfies the above equation we actually have total 4 different combination which that satisfy the equation.

**How many lattice points on a circle with radius 5?**

Output : 12 Below are lattice points on a circle with radius 5 and origin as (0, 0). (0,5), (0,-5), (5,0), (-5,0), (3,4), (-3,4), (-3,-4), (3,-4), (4,3), (-4,3), (-4,-3), (4,-3). are 12 lattice point. Recommended: Please solve it on “ PRACTICE ” first, before moving on to the solution.

### How do you find the centre of a circle?

Equation of a Circle: Centre is Origin: Consider an arbitrary point (P(x,y)) on the circle. Let (a) be the radius of the circle which is equal to (OP).